int(dx)/(16+x^2)dx=?
সঠিক উত্তরঃ
A.
1/4tan^(-1)(x/4)
Explanation: 
Another Explanation (5):
সমাধান:
\[\int \frac{dx}{16+x^2}\]
আমরা জানি, \[\int \frac{dx}{a^2+x^2} = \frac{1}{a} \tan^{-1}\left(\frac{x}{a}\right) + C\]
এখানে, \(a^2 = 16\) সুতরাং, \(a = 4\).
অতএব,
\[\int \frac{dx}{16+x^2} = \int \frac{dx}{4^2+x^2} = \frac{1}{4} \tan^{-1}\left(\frac{x}{4}\right) + C\]
সুতরাং, উত্তর: \(\frac{1}{4} \tan^{-1}\left(\frac{x}{4}\right)\) 🥳🎉
