int 1/x ( x+ 1/x )dx=?
Explanation: 
Another Explanation (5):
সমাধান:
\(\int \frac{1}{x} (x + \frac{1}{x}) dx\)
=\(\int (1 + \frac{1}{x^2}) dx\) 🤓
=\(\int 1 dx + \int \frac{1}{x^2} dx\) 🤔
= \(x + \int x^{-2} dx\)
= \(x + \frac{x^{-2+1}}{-2+1} + c\) 🤩
= \(x + \frac{x^{-1}}{-1} + c\)
= \(x - \frac{1}{x} + c\) ✅
সুতরাং, \(\int \frac{1}{x} (x + \frac{1}{x}) dx = x - \frac{1}{x} + c\) 🥳