Explanation: 
Another Explanation (5):
সমাধান:
আমরা জানি, \(cos2x = 2cos^2x - 1 = 1 - 2sin^2x\)।
অতএব,
\[
\begin{aligned}
\int \frac{1-cos2x}{1+cos2x} dx &= \int \frac{1-(1-2sin^2x)}{1+(2cos^2x-1)} dx \\
&= \int \frac{2sin^2x}{2cos^2x} dx \\
&= \int tan^2x dx \\
&= \int (sec^2x - 1) dx \\
&= \int sec^2x dx - \int 1 dx \\
&= tanx - x + C
\end{aligned}
\]
সুতরাং, \(\int \frac{1-cos2x}{1+cos2x} dx = tanx - x + C\) 🥳
উত্তর: \(tanx - x\) 😊
