Explanation: Billal comes \(4^{th}\). So, he must get more than 5 . The least possible value is 6 . Again, \(1^{st}\) position got 80 , leaving 120 for the rest four. To find the greatest value that Bilal can get, the \(5^{th}\) person must get the least amount, that is 5 . The rest 115 is to be distributed among the \(2^{nd}\), \(3^{rd}\) and Bilal. This can be done in two ways. \((40, 38, 37)\) and \((39, 38, 38)\). Since no repetition is allowed, the greatest possible value that Bilal can get is 37 .