Explanation: Since, AC and DE are not parallel, the only way the two triangles can be similar is if \(\angle A=\angle E\). Again, ratio of areas of similar triangle is equal to the square of the ratio of the similar sides. So, \(\frac{\text{area of ABC}}{\text{area of DBE}} = \left(\frac{8}{4}\right)^{2}\) or, area of ABC = \(4\times6=24\).
