Explanation: **First Day (4 slots: 1st Morning, 1st Afternoon, total max 4 steps):** H and L are performed. Remaining slots for Day 1: 2. K and M must be together. J is on Day 2. M and O must be before J (Day 2). O must be before P (Morning) and S. Since K and M must be done together (taking 2 slots), and they must be before J (Day 2), K and M must be the remaining two tasks on Day 1. **Day 1: H, L, K, M.** **Day 2 (4 slots):** J is mandatory. M and O must be completed before J. Since M is done on Day 1, O must be done on Day 2 before J (if J is in the afternoon) or on Day 1 (which would displace K and M). Let's check Day 2: J (1 slot) and O (1 slot). **Day 2: J, O, (2 remaining slots).** P must be in the morning. O must be before P. The earliest P can be is 2nd Day Morning. J is on Day 2. If O is in the 2nd Day Afternoon, J must be in the 3rd Day, which contradicts the condition. Let's re-evaluate the constraint: \(J\) after \(M\) and \(O\). \(O\) before \(P\) (morning) and \(S\). If H, L, K, M are Day 1 tasks (4 slots filled). O must be on Day 2. J is on Day 2. To have O before P (Morning) and have all steps done: P must be after O. If O is Day 2 morning, P can't be Day 2 morning (P before O is false). If O is Day 2 afternoon, P must be Day 3 morning (P must be morning). Therefore, P must be on the third day Morning.
