Explanation:Here, value of (n+1)-5p →5+1=63f →3+3=64d →4+2=6 6s →6+0=65p→5+1=63f→3+3=64d→4+2=66s→6+0=65p →5+1=63f →3+3=64d →4+2=66s →6+0=6 ∴ the value of (n + 1) is equal, that’s why, the orbital where the value of n is the highest, its energy is also the highest. [Hazari Sir: Edition-2022, Page-124]
