Explanation: 
Another Explanation (5):
bài giải:
\(tan 40^\circ \cdot tan 50^\circ \cdot tan 60^\circ\) 🤩
আমরা জানি, \(tan (90^\circ - \theta) = cot \theta\) এবং \(cot \theta = \frac{1}{tan \theta}\)। সুতরাং, \(tan \theta \cdot cot \theta = 1\)।
এখানে, \(tan 50^\circ = tan (90^\circ - 40^\circ) = cot 40^\circ\)
তাহলে, \(tan 40^\circ \cdot tan 50^\circ \cdot tan 60^\circ = tan 40^\circ \cdot cot 40^\circ \cdot tan 60^\circ\)
যেহেতু \(tan 40^\circ \cdot cot 40^\circ = 1\) 🥳, তাই
\(tan 40^\circ \cdot cot 40^\circ \cdot tan 60^\circ = 1 \cdot tan 60^\circ\)
আমরা জানি, \(tan 60^\circ = \sqrt{3}\)। অতএব,
\(1 \cdot tan 60^\circ = \sqrt{3}\) 😎
সুতরাং, \(tan 40^\circ \cdot tan 50^\circ \cdot tan 60^\circ = \sqrt{3}\) 🥰
