Explanation: 
Another Explanation (5):
সমাধান:
আমরা জানি, \( \sin^2 \theta = \frac{1 - \cos 2\theta}{2} \)
সুতরাং, \( \sin^2 \frac{x}{2} = \frac{1 - \cos x}{2} \)
অতএব, \( \int 2\sin^2 \frac{x}{2} \, dx = \int 2 \cdot \frac{1 - \cos x}{2} \, dx \)
\( = \int (1 - \cos x) \, dx \)
\( = \int 1 \, dx - \int \cos x \, dx \)
\( = x - \sin x + c \) 🥳
সুতরাং, \( \int 2\sin^2 \frac{x}{2} \, dx = x - \sin x + c \) 😎
উত্তর: \( x - \sin x + c \) 🎉
