Explanation: 
Another Explanation (5):
সমাধান:
ধরি, \(u = x + \ln x\)। 🧐
তাহলে, \(\frac{du}{dx} = 1 + \frac{1}{x}\) 🤔
সুতরাং, \(du = (1 + \frac{1}{x}) dx\) 🤩
এখন, \(\int (1 + \frac{1}{x}) (x + \ln x) dx = \int u du\) 🤓
আমরা জানি, \(\int u du = \frac{1}{2} u^2 + C\) 😍
অতএব, \(\int (1 + \frac{1}{x}) (x + \ln x) dx = \frac{1}{2} (x + \ln x)^2 + C\) 🥳
সুতরাং, উত্তর: \(\frac{1}{2} (x + \ln x)^2 + C\) 🎉