Explanation: 
Another Explanation (5):
bài giải:
\(A=\begin{bmatrix} 3 & 10 \\ 2 & 7 \end{bmatrix}\) 🧐
\(A^{-1} = \frac{1}{det(A)} adj(A)\) 🤔
এখন, \(det(A) = (3 \times 7) - (10 \times 2) = 21 - 20 = 1\) 😲
\(adj(A) = \begin{bmatrix} 7 & -10 \\ -2 & 3 \end{bmatrix}\) 🤓
সুতরাং, \(A^{-1} = \frac{1}{1} \begin{bmatrix} 7 & -10 \\ -2 & 3 \end{bmatrix} = \begin{bmatrix} 7 & -10 \\ -2 & 3 \end{bmatrix}\) 🎉