If y = x2 log x then d3y/dx3 is -
Explanation: 
Another Explanation (5): ```html
সমাধান:
y = x2 log x
প্রথম অন্তরকলন:
dy/dx = d/dx (x2 log x)
= x2 * (1/x) + log x * 2x
= x + 2x log x
দ্বিতীয় অন্তরকলন:
d2y/dx2 = d/dx (x + 2x log x)
= 1 + 2 * (x * (1/x) + log x * 1)
= 1 + 2 * (1 + log x)
= 1 + 2 + 2 log x
= 3 + 2 log x
তৃতীয় অন্তরকলন:
d3y/dx3 = d/dx (3 + 2 log x)
= 0 + 2 * (1/x)
= 2/x
অতএব, d3y/dx3 = 2/x 🥳
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