Explanation: 
Another Explanation (5):
দেওয়া আছে,
\(\sqrt{5} \sin\theta = \sqrt{3}\) এবং \(\sqrt{5} \cos\theta = 1\)
\(\sqrt{5} \cos\theta = 1\) হতে পাই,
\(\cos\theta = \frac{1}{\sqrt{5}}\) .....(1)
এবং \(\sqrt{5} \sin\theta = \sqrt{3}\) হতে পাই,
\(\sin\theta = \frac{\sqrt{3}}{\sqrt{5}}\) .....(2)
\( (2) \div (1) \) করে পাই,
\(\frac{\sin\theta}{\cos\theta} = \frac{\frac{\sqrt{3}}{\sqrt{5}}}{\frac{1}{\sqrt{5}}}\)
\(\Rightarrow \tan\theta = \sqrt{3}\)
আমরা জানি, \(\tan 60^\circ = \sqrt{3}\)
\(\Rightarrow \tan\theta = \tan 60^\circ \)
\(\therefore \theta = 60^\circ \) 🥳
