Explanation: Hz(2)-433; লঘুকরণ সমীকরণ মতে, V1×M1=V2×M2⇒=V2=V1×M1M2=50mL×0.5M×10000.01M×102500mLV_1 \times M_1 = V_2 \times M_2 \rArr = V_2 = \dfrac {V_1 \times M_1}{M_2} = \dfrac {50mL \times 0.5 M \times 1000}{0.01M \times 10} 2500mL\newlineV1×M1=V2×M2⇒=V2=M2V1×M1=0.01M×1050mL×0.5M×10002500mL∴ \therefore∴ পানি যোগ করতে হবে (2500−50)=2450mL(2500-50) = 2450mL(2500−50)=2450mL