Explanation: 
Another Explanation (5): ```html
Sin A = \(\frac{12}{13}\) হলে, tan A এর মান নির্ণয়:
আমরা জানি, \(sin^2 A + cos^2 A = 1\)
সুতরাং, \(cos^2 A = 1 - sin^2 A\)
\(cos^2 A = 1 - (\frac{12}{13})^2\)
\(cos^2 A = 1 - \frac{144}{169}\)
\(cos^2 A = \frac{169 - 144}{169}\)
\(cos^2 A = \frac{25}{169}\)
অতএব, \(cos A = \pm \frac{5}{13}\) 😃
এখন, \(tan A = \frac{sin A}{cos A}\) 🤓
যখন \(cos A = \frac{5}{13}\), তখন \(tan A = \frac{\frac{12}{13}}{\frac{5}{13}} = \frac{12}{5}\)
আবার, যখন \(cos A = -\frac{5}{13}\), তখন \(tan A = \frac{\frac{12}{13}}{-\frac{5}{13}} = -\frac{12}{5}\)
সুতরাং, \(tan A = \pm \frac{12}{5}\) 🎉
```
