Explanation: 
Another Explanation (5):
sinθsin(600-θ)sin(600+θ) = ? 🤔
আমরা জানি, sin(A+B)sin(A-B) = sin2A - sin2B 🤓
তাহলে, sin(600-θ)sin(600+θ) = sin2600 - sin2θ 😊
= (√3/2)2 - sin2θ
= 3/4 - sin2θ 😇
সুতরাং, sinθsin(600-θ)sin(600+θ) = sinθ(3/4 - sin2θ)
= (3sinθ)/4 - sin3θ 🤩
= (3sinθ - 4sin3θ)/4 🥳
আমরা ত্রিকোণমিতি থেকে জানি, sin3θ = 3sinθ - 4sin3θ 😎
অতএব, sinθsin(600-θ)sin(600+θ) = (sin3θ)/4 🤯
= 1/4 sin3θ 🤓
