Explanation: 
Another Explanation (5):
প্রশ্ন: ∫ dx/(3-4x)^(2/3) = ?
সমাধান:
ধরি, u = 3 - 4x
তাহলে, du = -4 dx
সুতরাং, dx = -du/4
এখন, ∫ dx/(3-4x)^(2/3) = ∫ (-du/4)/u^(2/3)
= -1/4 ∫ u^(-2/3) du
= -1/4 * (u^(-2/3 + 1))/(-2/3 + 1) + C [যেখানে C একটি ধ্রুবক]
= -1/4 * (u^(1/3))/(1/3) + C
= -3/4 * u^(1/3) + C
u এর মান বসিয়ে পাই,
= -3/4 * (3-4x)^(1/3) + C
অতএব, ∫ dx/(3-4x)^(2/3) = -3/4(3-4x)^(1/3) + C 🥳
সুতরাং, উত্তর: -3/4(3-4x)^(1/3) 🤩
