Explanation: 
Another Explanation (5):
প্রশ্ন: \( \sin^2 \left(\frac{\pi}{8}\right) + \sin^2 \left(\frac{5\pi}{8}\right) \) এর মান নির্ণয় করো। 🧐
আমরা জানি, \( \sin(\theta) = \cos\left(\frac{\pi}{2} - \theta\right) \)
তাহলে, \( \sin\left(\frac{5\pi}{8}\right) = \sin\left(\pi - \frac{3\pi}{8}\right) = \sin\left(\frac{3\pi}{8}\right) \) 🥳
আবার, \( \sin\left(\frac{3\pi}{8}\right) = \sin\left(\frac{\pi}{2} - \frac{\pi}{8}\right) = \cos\left(\frac{\pi}{8}\right) \) 🤩
সুতরাং, \( \sin^2 \left(\frac{5\pi}{8}\right) = \cos^2 \left(\frac{\pi}{8}\right) \) 🤓
এখন, \( \sin^2 \left(\frac{\pi}{8}\right) + \sin^2 \left(\frac{5\pi}{8}\right) = \sin^2 \left(\frac{\pi}{8}\right) + \cos^2 \left(\frac{\pi}{8}\right) \) 😎
আমরা জানি, \( \sin^2(\theta) + \cos^2(\theta) = 1 \) 🥰
অতএব, \( \sin^2 \left(\frac{\pi}{8}\right) + \sin^2 \left(\frac{5\pi}{8}\right) = 1 \) 🎉
