Mr. Adittya, a renowned engineer, designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 24-foot platform and caught it after it had traveled 23.25 yards. How many times did the ball bounce?
Explanation: প্রশ্নে বলা আছে, প্রতি bounce এ যতটুকূ উচ্চতা থেকে ফেনা হয়েছে, তার ঠিক অর্ধেক ওঠে। এক্ষেত্রে, 24 feet বা \(\frac{24}{3}=8\) yards থেকে ফেলা হয়েছে। So, after \(1^{st}\) bounce it travels \((8/2)+(8/2)=8\) yards, after \(2^{nd}\) bounce it travels \((4/2)+(4/2)=4\) yards, and so on it continues. অর্থাৎ \(8+4+4+2+2+1+1+.5+.5+.25=23.25\) yard দূরত্ব অতিক্রম করতে ৫টি bounce প্রয়োজন।]
