Explanation: 
Another Explanation (5): ```html
Sin A = 1/5 হলে, tan A এর মান নির্ণয়:
আমরা জানি, \(sin^2 A + cos^2 A = 1\)
সুতরাং, \(cos^2 A = 1 - sin^2 A\)
\(cos^2 A = 1 - (1/5)^2\)
\(cos^2 A = 1 - 1/25\)
\(cos^2 A = 24/25\)
অতএব, \(cos A = \pm \sqrt{24/25}\)
\(cos A = \pm \frac{\sqrt{24}}{5}\)
\(cos A = \pm \frac{2\sqrt{6}}{5}\)
এখন, \(tan A = \frac{sin A}{cos A}\)
\(tan A = \frac{1/5}{\pm \frac{2\sqrt{6}}{5}}\)
\(tan A = \pm \frac{1}{2\sqrt{6}}\)
সুতরাং, \(tan A = \pm \frac{1}{2\sqrt{6}}\) 🥳
```
