Explanation: 
Another Explanation (5):
সমাধান:
ধরি, \(u = \frac{1}{x}\)
তাহলে, \(\frac{du}{dx} = -\frac{1}{x^2}\)
সুতরাং, \(du = -\frac{1}{x^2} dx\)
অতএব, \(\frac{1}{x^2} dx = -du\)
এখন, \(\int \frac{1}{x^2} \sin\left(\frac{1}{x}\right) dx = \int \sin(u) (-du)\)
\( = -\int \sin(u) du\)
\( = - (-\cos(u)) + c\)
\( = \cos(u) + c\)
\( = \cos\left(\frac{1}{x}\right) + c\)
সুতরাং, \(\int \frac{1}{x^2} \sin\left(\frac{1}{x}\right) dx = \cos\left(\frac{1}{x}\right) + c\)
উত্তর: \(\cos\left(\frac{1}{x}\right) + c\) 🎉
