Explanation: 
Another Explanation (5):
সমাধান:
ধরি, \( sin \theta = z \)
তাহলে, \( cos \theta d\theta = dz \)
যখন \( \theta = 0 \), তখন \( z = sin(0) = 0 \)
যখন \( \theta = \frac{\pi}{2} \), তখন \( z = sin(\frac{\pi}{2}) = 1 \)
সুতরাং,
\( \int_{0}^{\frac{\pi}{2}} sin^5 \theta cos \theta d\theta = \int_{0}^{1} z^5 dz \)
\( = [\frac{z^6}{6}]_{0}^{1} \)
\( = \frac{1^6}{6} - \frac{0^6}{6} \)
\( = \frac{1}{6} - 0 \)
\( = \frac{1}{6} \)
অতএব, \( \int_{0}^{\frac{\pi}{2}} sin^5 \theta cos \theta d\theta = \frac{1}{6} \) 🥳
